Question: Consider
the following complex ions, P, Q and R
P
= [FeF6]3-, Q = [V(H2O)6]2+,
and R = [Fe(H2O)6]2+
What
is the correct order of the complex ions, according to their spin-only magnetic
moment values (in B.M.)?
A) R<Q<P
B) Q<R<P
C) R<P<Q
D) Q<P<R
Solution:
The formula used to calculate the spin-only
magnetic moment can be written as:
μ= √n(n+2) B.M.
Where n = no. of unpaired electron
Where n = no. of unpaired electron
So first let us find
out number of unpaired electron in each complex.
1)
P = [FeF6]3-
Charge on Fe in the complex: [FeF6]3-
X + (1x6) = -3
= +3
So number of unpaired
electron in Fe+3 = 3s2, 3p6,
3d5, 4s0
= 5
Magnetic moment = √5 (5+2)
=√35 B.M.
2)
Q = [V(H2O)6]2+
Charge on Fe in the complex: X +
(0x6) = +2
= +2
So number of unpaired
electron in V+2 = 3s2, 3p6,
3d3,
= 3
Magnetic moment = √3 (3+2)
=√15 B.M.
3) R = [Fe(H2O)6]2+
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